What is (\partial ^2)/(\partial y^2)(x^2-y^2) ?

The answer to (\partial ^2)/(\partial y^2)(x^2-y^2) is -2

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(\partial ^2)/(\partial y^2)(x^2-y^2)

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - y^{2})

- 2

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - y^{2})

\frac{\partial}{\partial y} (x^{2} - y^{2}) = - 2 y

= \frac{\partial}{\partial y} (- 2 y)

\frac{\partial}{\partial y} (- 2 y) = - 2

= - 2

\frac{\partial}{\partial x} (14 x e^{y})

x^{2} y^{^{'}} = y^{2} + x^{2}

\frac{d}{d x} ((x + 2) e^{- x})

\frac{d y}{d x} = \frac{x}{34 + x ^{2}}

\frac{d y}{d x} = 9 y e^{x + 3}

What is (\partial ^2)/(\partial y^2)(x^2-y^2) ?
The answer to (\partial ^2)/(\partial y^2)(x^2-y^2) is -2