What is the integral of (x^{1/3}-3^{1/3}) ?

The integral of (x^{1/3}-3^{1/3}) is 3/4 x^{4/3}-3^{1/3}x+C

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integral of (x^{1/3}-3^{1/3})

\int (x^{\frac{1}{3}} - 3^{\frac{1}{3}}) d x

\frac{3}{4} x^{\frac{4}{3}} - 3^{\frac{1}{3}} x + C

Solution steps

\int x^{\frac{1}{3}} - 3^{\frac{1}{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{1}{3}} d x - \int 3^{\frac{1}{3}} d x

\int x^{\frac{1}{3}} d x = \frac{3}{4} x^{\frac{4}{3}}

\int 3^{\frac{1}{3}} d x = 3^{\frac{1}{3}} x

= \frac{3}{4} x^{\frac{4}{3}} - 3^{\frac{1}{3}} x

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} - 3^{\frac{1}{3}} x + C

\frac{d}{d x} (x^{9} ln (7 x))

n = 1 \sum \infty \frac{1}{4 n ^{2} + 5}

\frac{d}{d x} (\frac{5 - sec ( x )}{tan ( x )})

y = 9

f (x) = \frac{x + 1}{x + 3}

What is the integral of (x^{1/3}-3^{1/3}) ?
The integral of (x^{1/3}-3^{1/3}) is 3/4 x^{4/3}-3^{1/3}x+C