What is the limit as x approaches-2 of \sqrt[3]{x+1} ?

The limit as x approaches-2 of \sqrt[3]{x+1} is cube root of-1

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limit as x approaches-2 of \sqrt[3]{x+1}

Solution steps

Plug in the value

x = - 2

Simplify

x \to 0 lim (\frac{ln ( 1 + 10 x )}{x})

\int sin (8 x) sin (5 x) d x

\int \frac{196 - x ^{2}}{x} d x

(1 + \frac{9}{x})^{x}

\int (4 x^{3} + 3 x^{2} + 2 x + 5) d x

What is the limit as x approaches-2 of \sqrt[3]{x+1} ?
The limit as x approaches-2 of \sqrt[3]{x+1} is cube root of-1