What is the tangent of y=(x+1)/(5-x),(7,-4) ?

The tangent of y=(x+1)/(5-x),(7,-4) is y= 3/2 x-29/2

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tangent of y=(x+1)/(5-x),(7,-4)

tangent of

y = \frac{x + 1}{5 - x}, (7, - 4)

y = \frac{3}{2} x - \frac{29}{2}

Solution steps

Find the slope of

y = \frac{x + 1}{5 - x} : \frac{d y}{d x} = \frac{6}{( 5 - x ) ^{2}}

Compute the slope of

y = \frac{x + 1}{5 - x}

(7, - 4) : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(7, - 4) : y = \frac{3}{2} x - \frac{29}{2}

y = \frac{3}{2} x - \frac{29}{2}

\frac{d}{d x} (x^{2} cos (\frac{1}{x ^{2}}))

x \to - 2 lim (\frac{x + 1}{x + 2})

y = x, y = 0, x = 25

y^{^{'}} + 2 y = 3 x

7 x + 4

What is the tangent of y=(x+1)/(5-x),(7,-4) ?
The tangent of y=(x+1)/(5-x),(7,-4) is y= 3/2 x-29/2