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Popular >

integral from 0 to 9 of |2x-9|

Solution

\int_{0}^{9} ∣ 2 x - 9 ∣ d x

Solution

\frac{81}{2}

+1

Decimal Notation

40.5

Solution steps

\int_{0}^{9} ∣ 2 x - 9 ∣ d x

Eliminate Absolutes

= \int_{0}^{\frac{9}{2}} - 2 x + 9 d x + \int_{\frac{9}{2}}^{9} 2 x - 9 d x

\int_{0}^{\frac{9}{2}} - 2 x + 9 d x = \frac{81}{4}

\int_{\frac{9}{2}}^{9} 2 x - 9 d x = \frac{81}{4}

= \frac{81}{4} + \frac{81}{4}

Simplify

\frac{81}{4} + \frac{81}{4} : \frac{81}{2}

= \frac{81}{2}

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x \to 3 - lim (\frac{e ^{2}}{x - 3})

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\int \frac{x ^{2}}{( 1 - x ^{3} ) ^{5}} d x

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\frac{d}{d x} (\frac{1}{x ^{2} + 3})

derivative of (\sqrt[3]{x}/(x^3+1))

integral of (cos(x))/(8-sin(x))

\int \frac{cos ( x )}{8 - sin ( x )} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 9 of |2x-9| ?
The integral from 0 to 9 of |2x-9| is 81/2