What is the integral from 0 to pi of 4sin(x) ?

The integral from 0 to pi of 4sin(x) is 8

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integral from 0 to pi of 4sin(x)

\int_{0}^{π} 4 sin (x) d x

8

Solution steps

\int_{0}^{π} 4 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 4 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 4 \cdot 2

Simplify

= 8

\frac{\partial}{\partial y} (2 x ln (y))

x \to 0 + lim (2 - \frac{3}{x ^{\frac{1}{3}}})

\int \frac{9 e ^{9 x}}{5 + e ^{9 x}} d x

\frac{y ^{^{'}} - e ^{- t} + 6}{y} = - 6, y (0) = 1

\frac{\partial}{\partial x} (5 sin (2 x) cos (5 y))

What is the integral from 0 to pi of 4sin(x) ?
The integral from 0 to pi of 4sin(x) is 8