What is the derivative of asin(5x+bcos(5x)) ?

The derivative of asin(5x+bcos(5x)) is acos(5x)*5-5bsin(5x)

What is the first derivative of asin(5x+bcos(5x)) ?

The first derivative of asin(5x+bcos(5x)) is acos(5x)*5-5bsin(5x)

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\frac{d}{d x} (a sin (5 x) + b cos (5 x))

a cos (5 x) \cdot 5 - 5 b sin (5 x)

Solution steps

\frac{d}{d x} (a sin (5 x) + b cos (5 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a sin (5 x)) + \frac{d}{d x} (b cos (5 x))

\frac{d}{d x} (a sin (5 x)) = a cos (5 x) \cdot 5

\frac{d}{d x} (b cos (5 x)) = - 5 b sin (5 x)

= a cos (5 x) \cdot 5 - 5 b sin (5 x)

y^{^{'}} = - y

\frac{x ^{6}}{5 - x ^{5}}

\int \frac{1}{25 x ^{2} - 4} d x

\frac{\partial}{\partial y} (e^{x} sin (y) + 3 y)

\int \frac{1}{x ^{2} + 3 x - 4} d x

What is the derivative of asin(5x+bcos(5x)) ?
The derivative of asin(5x+bcos(5x)) is acos(5x)*5-5bsin(5x)
What is the first derivative of asin(5x+bcos(5x)) ?
The first derivative of asin(5x+bcos(5x)) is acos(5x)*5-5bsin(5x)