What is the integral of (cos(u))/(3a) ?

The integral of (cos(u))/(3a) is 1/(3a)sin(u)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (cos(u))/(3a)

\int \frac{cos ( u )}{3 a} d u

\frac{1}{3 a} sin (u) + C

Solution steps

\int \frac{cos ( u )}{3 a} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3 a} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{3 a} sin (u)

Add a constant to the solution

= \frac{1}{3 a} sin (u) + C

\int_{0}^{1} 12 cos (x^{2}) d x

x \to \frac{π}{4} lim (cot (4 x))

n = 0 \sum \infty sin (2 n)

\frac{x + x}{x ^{2}}

\frac{\partial}{\partial x} (4 x ln (x y))

What is the integral of (cos(u))/(3a) ?
The integral of (cos(u))/(3a) is 1/(3a)sin(u)+C