What is derivative of f(x)=θsin(θ) ?

The answer to derivative of f(x)=θsin(θ) is derivative of θ=0

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derivative of f(x)=θsin(θ)

derivative of

f (x) = θ sin (θ)

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = θ sin (θ)

Treat

θ

θ (x)

Differentiate both sides:

0 = \frac{d}{d x} (θ) sin (θ) + cos (θ) \frac{d}{d x} (θ) θ

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

\frac{d}{d x} (- \frac{1}{( x + 2 ) ^{2}})

\int sec (a x) d x

\frac{d}{d x} ((4 x^{2} - 14)^{- 10})

\int \frac{1}{( x ^{2} - 6 x + 25 ) ^{3}} d x

\int_{1}^{2} \frac{- 8 ln ( x )}{x ^{2}} d x

What is derivative of f(x)=θsin(θ) ?
The answer to derivative of f(x)=θsin(θ) is derivative of θ=0