What is the derivative of t^{4/3} ?

The derivative of t^{4/3} is (4t^{1/3})/3

What is the first derivative of t^{4/3} ?

The first derivative of t^{4/3} is (4t^{1/3})/3

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derivative of

t^{\frac{4}{3}}

\frac{4 t ^{\frac{1}{3}}}{3}

Solution steps

\frac{d}{d t} (t^{\frac{4}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{3} t^{\frac{4}{3} - 1}

Simplify

\frac{4}{3} t^{\frac{4}{3} - 1} : \frac{4 t ^{\frac{1}{3}}}{3}

= \frac{4 t ^{\frac{1}{3}}}{3}

f (x) = x^{3} - 9 x + 4, (3, 4)

\frac{d y}{d x} = \frac{( x - y )}{( x + y )}

(1 + x)^{- 5}

\frac{\partial}{\partial y} (\frac{1}{y} e^{x y})

\int_{1}^{13} \frac{x - 1}{72} d x

What is the derivative of t^{4/3} ?
The derivative of t^{4/3} is (4t^{1/3})/3
What is the first derivative of t^{4/3} ?
The first derivative of t^{4/3} is (4t^{1/3})/3