What is the d/(dt)(-5sin(t)) ?

The d/(dt)(-5sin(t)) is -5cos(t)

What is the first d/(dt)(-5sin(t)) ?

The first d/(dt)(-5sin(t)) is -5cos(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (- 5 sin (t))

- 5 cos (t)

Solution steps

\frac{d}{d t} (- 5 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= - 5 cos (t)

y = x + \frac{2}{x}, (2, 3)

\int t^{4} e^{- t^{5}} d t

\frac{d ^{2}}{d x ^{2}} (- e^{- x^{2}})

\frac{\partial}{\partial x} (A x + B y + C x^{2} y)

5 t^{2}