What is the solution for derivative of y=(x+y+3)^2 ?

The solution for derivative of y=(x+y+3)^2 is y=tan(x+c_{1})-x-3

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derivative of y=(x+y+3)^2

\frac{d}{d x} y = (x + y + 3)^{2}

y = tan (x + c_{1}) - x - 3

Solution steps

\frac{d y}{d x} = (x + y + 3)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x - 3

y = tan (x + c_{1}) - x - 3

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What is the solution for derivative of y=(x+y+3)^2 ?
The solution for derivative of y=(x+y+3)^2 is y=tan(x+c_{1})-x-3