What is (\partial)/(\partial x)(2x^2-4x+1) ?

The answer to (\partial)/(\partial x)(2x^2-4x+1) is 4x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^2-4x+1)

\frac{\partial}{\partial x} (2 x^{2} - 4 x + 1)

4 x - 4

Solution steps

\frac{\partial}{\partial x} (2 x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) - \frac{\partial}{\partial x} (4 x) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (1) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

\int (3 - 2 x)^{2} d x

f (x) = \frac{1}{4} x^{8}

\frac{d}{d x} (\frac{1 - sin ( x )}{1 - cos ( x )})

t^{3} cos (t)

\int \frac{1}{x ^{4} + x} d x

What is (\partial)/(\partial x)(2x^2-4x+1) ?
The answer to (\partial)/(\partial x)(2x^2-4x+1) is 4x-4