What is inverse oflaplace {1/(s^3)} ?

The answer to inverse oflaplace {1/(s^3)} is (t^2)/2

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inverse oflaplace {1/(s^3)}

inverse laplace

{\frac{1}{s ^{3}}}

\frac{t ^{2}}{2}

Solution steps

L^{- 1} {\frac{1}{s ^{3}}}

= L^{- 1} {\frac{1}{2} \cdot \frac{2}{s ^{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{2} L^{- 1} {\frac{2}{s ^{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{2}{s ^{3}}} = t^{2}

= \frac{1}{2} t^{2}

= \frac{t ^{2}}{2}

\int sin^{3} (15 x) d x

\frac{1}{( s ^{2} + 1 )}

f (x) = 4 ln (x)

f (x) = \frac{6}{4 x + 1}

x \to - 3.1 lim (f (x))

What is inverse oflaplace {1/(s^3)} ?
The answer to inverse oflaplace {1/(s^3)} is (t^2)/2