What is the derivative of 9sin(4x) ?

The derivative of 9sin(4x) is 36cos(4x)

What is the first derivative of 9sin(4x) ?

The first derivative of 9sin(4x) is 36cos(4x)

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\frac{d}{d x} (9 sin (4 x))

36 cos (4 x)

Solution steps

\frac{d}{d x} (9 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 9 cos (4 x) \cdot 4

Simplify

= 36 cos (4 x)

\frac{36}{( 1 + 3 x ) ^{3}}

\int \frac{26}{( x ^{2} - 1 ) ^{2}} d x

\frac{0.07 s}{7 s ^{2} + 19980}

e^{- 7 x}, x \geq 0

\frac{d}{d x} (\frac{e ^{x}}{2 x ^{2} + 1})

What is the derivative of 9sin(4x) ?
The derivative of 9sin(4x) is 36cos(4x)
What is the first derivative of 9sin(4x) ?
The first derivative of 9sin(4x) is 36cos(4x)