What is the sum from n=1 to infinity of 5/(6n+4) ?

The sum from n=1 to infinity of 5/(6n+4) is diverges

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sum from n=1 to infinity of 5/(6n+4)

n = 1 \sum \infty \frac{5}{6 n + 4}

diverges

Solution steps

n = 1 \sum \infty \frac{5}{6 n + 4}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{1}{6 n + 4}

Apply Series Limit Comparison Test:

diverges

= 5 diverges

= diverges

\frac{\partial}{\partial x} (16 - x^{2})

f (x) = \frac{cos ( x )}{2 + sin ( x )}

y^{^{''}} - 2 y^{^{'}} - 3 y = 10 e^{4 x}

f (x) = \frac{x}{x ^{2} + 7 x + 6}

3 + t

What is the sum from n=1 to infinity of 5/(6n+4) ?
The sum from n=1 to infinity of 5/(6n+4) is diverges