What is the integral of 1/(x*ln(x^6)) ?

The integral of 1/(x*ln(x^6)) is 1/6 ln(6|ln(x)|)+C

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integral of 1/(x*ln(x^6))

\int \frac{1}{x \cdot ln ( x ^{6} )} d x

\frac{1}{6} ln (6 ∣ ln (x) ∣) + C

Solution steps

\int \frac{1}{x ln ( x ^{6} )} d x

Apply u-substitution

: \int \frac{1}{6 u ln ( u )} d u

= \int \frac{1}{6 u ln ( u )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int \frac{1}{u ln ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \frac{1}{6} \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= \frac{1}{6} ln ∣ v ∣

Substitute back

= \frac{1}{6} ln ln (x^{6})

Simplify

\frac{1}{6} ln ln (x^{6}) : \frac{1}{6} ln (6 ∣ ln (x) ∣)

= \frac{1}{6} ln (6 ∣ ln (x) ∣)

Add a constant to the solution

= \frac{1}{6} ln (6 ∣ ln (x) ∣) + C

x^{^{''}} + 16 x = 0

\int_{1}^{2} \frac{3 x - 1}{3 x} d x

\int \frac{8}{x ^{2} 4 - x ^{2}} d x

\int csc (v) d v

y = sin^{3} (x)

What is the integral of 1/(x*ln(x^6)) ?
The integral of 1/(x*ln(x^6)) is 1/6 ln(6|ln(x)|)+C