What is the derivative of sqrt(x)+(x^6^3) ?

The derivative of sqrt(x)+(x^6^3) is 1/(2sqrt(x))+18x^{17}

What is the first derivative of sqrt(x)+(x^6^3) ?

The first derivative of sqrt(x)+(x^6^3) is 1/(2sqrt(x))+18x^{17}

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\frac{d}{d x} (x + (x^{6})^{3})

\frac{1}{2 x} + 18 x^{17}

Solution steps

\frac{d}{d x} (x + (x^{6})^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} ((x^{6})^{3})

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} ((x^{6})^{3}) = 18 x^{17}

= \frac{1}{2 x} + 18 x^{17}

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t^{2} \frac{d x}{d t} = 2 t x + 1

\int \frac{1}{x ^{2} ( 1 + \frac{1}{x} ) ^{3}} d x

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 36 x + 5)

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What is the derivative of sqrt(x)+(x^6^3) ?
The derivative of sqrt(x)+(x^6^3) is 1/(2sqrt(x))+18x^{17}
What is the first derivative of sqrt(x)+(x^6^3) ?
The first derivative of sqrt(x)+(x^6^3) is 1/(2sqrt(x))+18x^{17}