What is the derivative of 2+1/(x^2) ?

The derivative of 2+1/(x^2) is -2/(x^3)

What is the first derivative of 2+1/(x^2) ?

The first derivative of 2+1/(x^2) is -2/(x^3)

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\frac{d}{d x} (2 + \frac{1}{x ^{2}})

- \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (2 + \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 0 - \frac{2}{x ^{3}}

Simplify

= - \frac{2}{x ^{3}}

\frac{\partial}{\partial x} (3 x^{2} + 2 y)

\int (cos^{2} (x)) d x

\int (2^{x}) d x

x \to 7 - lim (4 x)

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{3 + x})

What is the derivative of 2+1/(x^2) ?
The derivative of 2+1/(x^2) is -2/(x^3)
What is the first derivative of 2+1/(x^2) ?
The first derivative of 2+1/(x^2) is -2/(x^3)