What is the solution for y^'=2+3y^2 ?

The solution for y^'=2+3y^2 is y=(sqrt(2)tan(sqrt(6)(t+c_{1})))/(sqrt(3))

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y^'=2+3y^2

y^{^{'}} = 2 + 3 y^{2}

y = \frac{2 tan ( 6 ( t + c _{1} ) )}{3}

Solution steps

y^{'} (t) = 2 + 3 y^{2}

Solve separable ODE:

y = \frac{2 tan ( 6 ( t + c _{1} ) )}{3}

y = \frac{2 tan ( 6 ( t + c _{1} ) )}{3}

\frac{d}{d x} ((\frac{x}{x + 1})^{2016})

\int \frac{1}{P - Z} + \frac{1}{Z} d Z

n = 1 \sum \infty \frac{3 n}{n !}

\int csc^{3} (x) \cdot sec (x) d x

\int (x^{2} + a x - 3)^{2} d x

What is the solution for y^'=2+3y^2 ?
The solution for y^'=2+3y^2 is y=(sqrt(2)tan(sqrt(6)(t+c_{1})))/(sqrt(3))