What is the derivative of y=2x^3+3x^2-12x+1 ?

The derivative of y=2x^3+3x^2-12x+1 is 6x^2+6x-12

What is the first derivative of y=2x^3+3x^2-12x+1 ?

The first derivative of y=2x^3+3x^2-12x+1 is 6x^2+6x-12

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derivative of

y = 2 x^{3} + 3 x^{2} - 12 x + 1

6 x^{2} + 6 x - 12

Solution steps

\frac{d}{d x} (2 x^{3} + 3 x^{2} - 12 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (12 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (1) = 0

= 6 x^{2} + 6 x - 12 + 0

Simplify

= 6 x^{2} + 6 x - 12

\frac{\partial}{\partial x} (ln (3 x - 2 y))

\int cos (3 - 5 x) d x

\frac{d}{d x} (x \cdot e^{y})

\int \frac{( x + 2 )}{x ^{2} + 4} d x

- 4 x^{2} y + y^{^{'}} = - 10 x^{2}

What is the derivative of y=2x^3+3x^2-12x+1 ?
The derivative of y=2x^3+3x^2-12x+1 is 6x^2+6x-12
What is the first derivative of y=2x^3+3x^2-12x+1 ?
The first derivative of y=2x^3+3x^2-12x+1 is 6x^2+6x-12