What is the derivative of f(x)=-2x^2+8 ?

The derivative of f(x)=-2x^2+8 is -4x

What is the first derivative of f(x)=-2x^2+8 ?

The first derivative of f(x)=-2x^2+8 is -4x

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derivative of

f (x) = - 2 x^{2} + 8

- 4 x

Solution steps

\frac{d}{d x} (- 2 x^{2} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (8)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8) = 0

= - 4 x + 0

Simplify

= - 4 x

\int (ln (x) + 4 x) d x

\int (x + 3) 8 - x d x

2 x + \frac{5}{x}

\frac{d}{d x} (cos (x) - cos^{2} (x))

\frac{d}{d x} (x^{3} + 3 x^{2})

What is the derivative of f(x)=-2x^2+8 ?
The derivative of f(x)=-2x^2+8 is -4x
What is the first derivative of f(x)=-2x^2+8 ?
The first derivative of f(x)=-2x^2+8 is -4x