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Popular >

integral of-16x^2

Solution

\int - 16 x^{2} d x

Solution

- \frac{16 x ^{3}}{3} + C

Solution steps

\int - 16 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 16 \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= - 16 \cdot \frac{x ^{3}}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{16 x ^{3}}{3}

Add a constant to the solution

= - \frac{16 x ^{3}}{3} + C

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\int t^{2} sin (t^{3}) d t

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\int (x - 1)^{10} (x + 3)^{2} d x

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\int \frac{2 ^{x}}{5 ^{x}} d x

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\frac{d}{d x} (\frac{3}{sin ( x ) + cos ( x )})

integral of (x^2)/(\sqrt[3]{1+x^3)}

Frequently Asked Questions (FAQ)

What is the integral of-16x^2 ?
The integral of-16x^2 is -(16x^3)/3+C