What is (\partial}{\partial x}(-\frac{8x)/y) ?

The answer to (\partial}{\partial x}(-\frac{8x)/y) is -8/y

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(\partial}{\partial x}(-\frac{8x)/y)

\frac{\partial}{\partial x} (- \frac{8 x}{y})

- \frac{8}{y}

Solution steps

\frac{\partial}{\partial x} (- \frac{8 x}{y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{8}{y} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - \frac{8}{y} \cdot 1

Simplify

= - \frac{8}{y}

x \to 2 - lim (2 - x - 2)

\int \frac{8 t - 3}{t + 1} d t

x \to 4 lim (x^{2} + 5 - x)

t^{2} y^{^{''}} + 3 t y^{^{'}} - 8 y = 0

What is (\partial}{\partial x}(-\frac{8x)/y) ?
The answer to (\partial}{\partial x}(-\frac{8x)/y) is -8/y