What is the integral of sec(2x) ?

The integral of sec(2x) is 1/2 ln|tan(2x)+sec(2x)|+C

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integral of sec(2x)

\int sec (2 x) d x

\frac{1}{2} ln ∣ tan (2 x) + sec (2 x) ∣ + C

Solution steps

\int sec (2 x) d x

Apply u-substitution

: \int sec (u) \frac{1}{2} d u

= \int sec (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec (u) d u

Use the common integral:

\int sec (u) d u = ln ∣ tan (u) + sec (u) ∣

= \frac{1}{2} ln ∣ tan (u) + sec (u) ∣

Substitute back

u = 2 x

= \frac{1}{2} ln ∣ tan (2 x) + sec (2 x) ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ tan (2 x) + sec (2 x) ∣ + C

y = 2 x^{3} - 2 x

(cos^{2} (x))^{^{'}}

(- 6, - 4), (- 4, 0)

\int_{- 1}^{2} x^{2} - x - 2 d x

\frac{\partial}{\partial x} (x ln (x))

What is the integral of sec(2x) ?
The integral of sec(2x) is 1/2 ln|tan(2x)+sec(2x)|+C