What is the solution for (dy)/(dx)=2xy^2+3x^2y^2 ?

The solution for (dy)/(dx)=2xy^2+3x^2y^2 is y=-1/(x^3+x^2+c_{1)}

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(dy)/(dx)=2xy^2+3x^2y^2

\frac{d y}{d x} = 2 x y^{2} + 3 x^{2} y^{2}

y = - \frac{1}{x ^{3} + x ^{2} + c _{1}}

Solution steps

\frac{d y}{d x} = 2 x y^{2} + 3 x^{2} y^{2}

Solve separable ODE:

y = - \frac{1}{x ^{3} + x ^{2} + c _{1}}

y = - \frac{1}{x ^{3} + x ^{2} + c _{1}}

f (t) = \frac{cos ( t )}{t ^{7}}

x \to 2 lim (5 x - 2)

\frac{d}{d x} (x cos (y - x))

\int cos (4 x + 5) d x

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What is the solution for (dy)/(dx)=2xy^2+3x^2y^2 ?
The solution for (dy)/(dx)=2xy^2+3x^2y^2 is y=-1/(x^3+x^2+c_{1)}