What is the derivative of sin(x+2/9 cot(x)) ?

The derivative of sin(x+2/9 cot(x)) is cos(x)-2/9 csc^2(x)

What is the first derivative of sin(x+2/9 cot(x)) ?

The first derivative of sin(x+2/9 cot(x)) is cos(x)-2/9 csc^2(x)

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\frac{d}{d x} (sin (x) + \frac{2}{9} cot (x))

cos (x) - \frac{2}{9} csc^{2} (x)

Solution steps

\frac{d}{d x} (sin (x) + \frac{2}{9} cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) + \frac{d}{d x} (\frac{2}{9} cot (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (\frac{2}{9} cot (x)) = - \frac{2}{9} csc^{2} (x)

= cos (x) - \frac{2}{9} csc^{2} (x)

ln (14 x)

\frac{d}{d x} (\frac{108}{x})

f (x) = (2 t - 1) (6 t - 6)^{- 1}

\frac{d}{d x} (\frac{332}{1 + 8.61 e ^{- 0.863 x}})

\int 21 x^{2} d x

What is the derivative of sin(x+2/9 cot(x)) ?
The derivative of sin(x+2/9 cot(x)) is cos(x)-2/9 csc^2(x)
What is the first derivative of sin(x+2/9 cot(x)) ?
The first derivative of sin(x+2/9 cot(x)) is cos(x)-2/9 csc^2(x)