What is the derivative of sqrt(3-7x) ?

The derivative of sqrt(3-7x) is -7/(2sqrt(3-7x))

What is the first derivative of sqrt(3-7x) ?

The first derivative of sqrt(3-7x) is -7/(2sqrt(3-7x))

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derivative of

3 - 7 x

- \frac{7}{2 3 - 7 x}

Solution steps

\frac{d}{d x} (3 - 7 x)

Apply the chain rule:

\frac{1}{2 3 - 7 x} \frac{d}{d x} (3 - 7 x)

= \frac{1}{2 3 - 7 x} \frac{d}{d x} (3 - 7 x)

\frac{d}{d x} (3 - 7 x) = - 7

= \frac{1}{2 3 - 7 x} (- 7)

Simplify

\frac{1}{2 3 - 7 x} (- 7) : - \frac{7}{2 3 - 7 x}

= - \frac{7}{2 3 - 7 x}

x \to 0 lim (\frac{∣ 3 x ∣}{x})

\int cos (θ^{2}) d θ

\int_{- π}^{2} sin (t) d t

f (x) = lo g_{5} (x)

\int e^{\frac{3}{200} t} 3 d t

What is the derivative of sqrt(3-7x) ?
The derivative of sqrt(3-7x) is -7/(2sqrt(3-7x))
What is the first derivative of sqrt(3-7x) ?
The first derivative of sqrt(3-7x) is -7/(2sqrt(3-7x))