What is the derivative of (4x+1^2) ?

The derivative of (4x+1^2) is 8(4x+1)

What is the first derivative of (4x+1^2) ?

The first derivative of (4x+1^2) is 8(4x+1)

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\frac{d}{d x} ((4 x + 1)^{2})

8 (4 x + 1)

Solution steps

\frac{d}{d x} ((4 x + 1)^{2})

Apply the chain rule:

2 (4 x + 1) \frac{d}{d x} (4 x + 1)

= 2 (4 x + 1) \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 2 (4 x + 1) \cdot 4

Simplify

= 8 (4 x + 1)

x \frac{d y}{d x} + y = e^{x}, y (1) = 2

\int 9 x^{2} sec (x^{3}) tan (x^{3}) d x

f (x) = sec (cos (x))

\int 2 x^{2} + x d x

\frac{d}{d x} (11 arctan (x))

What is the derivative of (4x+1^2) ?
The derivative of (4x+1^2) is 8(4x+1)
What is the first derivative of (4x+1^2) ?
The first derivative of (4x+1^2) is 8(4x+1)