What is the derivative of 8e^x+xe^x ?

The derivative of 8e^x+xe^x is 9e^x+e^xx

What is the first derivative of 8e^x+xe^x ?

The first derivative of 8e^x+xe^x is 9e^x+e^xx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (8 e^{x} + x e^{x})

9 e^{x} + e^{x} x

Solution steps

\frac{d}{d x} (8 e^{x} + x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 e^{x}) + \frac{d}{d x} (x e^{x})

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

= 8 e^{x} + e^{x} + e^{x} x

Simplify

= 9 e^{x} + e^{x} x

9 (t + 1) y^{^{'}} - 5 y = 20 t

\frac{\partial}{\partial s} (ln (r^{2} + s^{2} + 2))

\int e^{x} 25 - e^{2 x} d x

f (x) = x \cdot e^{x}

\frac{4}{( s ^{3} + 4 s ^{2} + 8 s )}

What is the derivative of 8e^x+xe^x ?
The derivative of 8e^x+xe^x is 9e^x+e^xx
What is the first derivative of 8e^x+xe^x ?
The first derivative of 8e^x+xe^x is 9e^x+e^xx