What is the slope ofintercept (z,2),(-2,-6) ?

The slope ofintercept (z,2),(-2,-6) is y=-8/(-2-z)z+2+(8z)/(-2-z)

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slope ofintercept (z,2),(-2,-6)

slope intercept

(z, 2), (- 2, - 6)

y = - \frac{8}{- 2 - z} z + 2 + \frac{8 z}{- 2 - z}

Solution steps

Compute the slope

(z, 2), (- 2, - 6) : m = - \frac{8}{- 2 - z}

Compute the

y

intercept:

b = 2 + \frac{8 z}{- 2 - z}

Construct the line equation

y = mx + b

where

m = - \frac{8}{- 2 - z}

and

b = 2 + \frac{8 z}{- 2 - z}

y = - \frac{8}{- 2 - z} z + 2 + \frac{8 z}{- 2 - z}

\int 6 x sec (3 x^{2}) tan (3 x^{2}) d x

x^{2} y^{^{''}} + x y^{^{'}} + 25 y = 0

\frac{\partial}{\partial x} (x^{2} + y^{2})

\int_{- 1}^{1} sec^{3} (x) d x

f (x) = \frac{( 2 x + 1 )}{x + 2}, at x = 1

What is the slope ofintercept (z,2),(-2,-6) ?
The slope ofintercept (z,2),(-2,-6) is y=-8/(-2-z)z+2+(8z)/(-2-z)