What is the d/(dθ)(asec^2(θ/2)) ?

The d/(dθ)(asec^2(θ/2)) is asec^2(θ/2)tan(θ/2)

What is the first d/(dθ)(asec^2(θ/2)) ?

The first d/(dθ)(asec^2(θ/2)) is asec^2(θ/2)tan(θ/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d θ} (a sec^{2} (\frac{θ}{2}))

a sec^{2} (\frac{θ}{2}) tan (\frac{θ}{2})

Solution steps

\frac{d}{d θ} (a sec^{2} (\frac{θ}{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d θ} (sec^{2} (\frac{θ}{2}))

Apply the chain rule:

2 sec (\frac{θ}{2}) \frac{d}{d θ} (sec (\frac{θ}{2}))

= 2 sec (\frac{θ}{2}) \frac{d}{d θ} (sec (\frac{θ}{2}))

\frac{d}{d θ} (sec (\frac{θ}{2})) = sec (\frac{θ}{2}) tan (\frac{θ}{2}) \frac{1}{2}

= a \cdot 2 sec (\frac{θ}{2}) sec (\frac{θ}{2}) tan (\frac{θ}{2}) \frac{1}{2}

Simplify

a \cdot 2 sec (\frac{θ}{2}) sec (\frac{θ}{2}) tan (\frac{θ}{2}) \frac{1}{2} : a sec^{2} (\frac{θ}{2}) tan (\frac{θ}{2})

= a sec^{2} (\frac{θ}{2}) tan (\frac{θ}{2})

x \to - 1 lim (3 x^{2} - 7 x - 4)

\int (4 x^{3} - 2)^{2} d x

\frac{d}{d x} (\frac{e ^{x}}{x ^{4} + 1})

\frac{d}{d x} (x^{6} - 1)

\int \frac{1}{x 4 x + 49} d x

What is the d/(dθ)(asec^2(θ/2)) ?
The d/(dθ)(asec^2(θ/2)) is asec^2(θ/2)tan(θ/2)
What is the first d/(dθ)(asec^2(θ/2)) ?
The first d/(dθ)(asec^2(θ/2)) is asec^2(θ/2)tan(θ/2)