What is the integral of 3y^2z+ye^x ?

The integral of 3y^2z+ye^x is ye^x+3y^2zx+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3y^2z+ye^x

\int 3 y^{2} z + y e^{x} d x

y e^{x} + 3 y^{2} z x + C

Solution steps

\int 3 y^{2} z + y e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int y e^{x} d x + \int 3 y^{2} z d x

\int y e^{x} d x = y e^{x}

\int 3 y^{2} z d x = 3 y^{2} z x

= y e^{x} + 3 y^{2} z x

Add a constant to the solution

= y e^{x} + 3 y^{2} z x + C

\int t (t - 1)^{12} d t

\frac{\partial}{\partial x} (sin (5 x - 2 y))

\frac{\partial}{\partial x} (2 y e^{4 x^{2} - 6 y})

f (x) = - x

x \to \infty lim (- 3, x)

What is the integral of 3y^2z+ye^x ?
The integral of 3y^2z+ye^x is ye^x+3y^2zx+C