What is the derivative of 1/(3x^3) ?

The derivative of 1/(3x^3) is -1/(x^4)

What is the first derivative of 1/(3x^3) ?

The first derivative of 1/(3x^3) is -1/(x^4)

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derivative of

\frac{1}{3 x ^{3}}

- \frac{1}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{3} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} (- 3 x^{- 3 - 1})

Simplify

\frac{1}{3} (- 3 x^{- 3 - 1}) : - \frac{1}{x ^{4}}

= - \frac{1}{x ^{4}}

\int (\frac{24 x}{3 - 4 x ^{2}}) d x

\frac{d}{d x} (2 (cos (\frac{x}{2}) - \frac{2}{2}))

\int_{2}^{3} 4 e^{4 x} d x

y^{^{'}} + 3 y = t e^{4 t}

What is the derivative of 1/(3x^3) ?
The derivative of 1/(3x^3) is -1/(x^4)
What is the first derivative of 1/(3x^3) ?
The first derivative of 1/(3x^3) is -1/(x^4)