What is the integral of (x-240)/(200) ?

The integral of (x-240)/(200) is 1/200 ((x^2)/2-240x)+C

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integral of (x-240)/(200)

\int \frac{x - 240}{200} d x

\frac{1}{200} (\frac{x ^{2}}{2} - 240 x) + C

Solution steps

\int \frac{x - 240}{200} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{200} \cdot \int x - 240 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{200} (\int x d x - \int 240 d x)

\int x d x = \frac{x ^{2}}{2}

\int 240 d x = 240 x

= \frac{1}{200} (\frac{x ^{2}}{2} - 240 x)

Add a constant to the solution

= \frac{1}{200} (\frac{x ^{2}}{2} - 240 x) + C

n = 1 \sum \infty \frac{7}{n ^{2} + 25}

\int_{0}^{\frac{1}{2}} \frac{5}{1 + 4 x ^{2}} d x

e^{x} (3 x^{2} - x + 1)

\frac{\partial}{\partial y} (e^{- x y^{2}} + y^{3} x^{4})

x y

What is the integral of (x-240)/(200) ?
The integral of (x-240)/(200) is 1/200 ((x^2)/2-240x)+C