What is the tangent of-2x^2 ?

The tangent of-2x^2 is y=-4a_{0}x+2a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of-2x^2

tangent of

- 2 x^{2}

y = - 4 a_{0} x + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 a_{0}^{2})

Find the slope of

y = - 2 x^{2} : \frac{d y}{d x} = - 4 x

Compute the slope of

y = - 2 x^{2}

x = a_{0} : m = - 4 a_{0}

Find the line with slope m=

- 4 a_{0}

and passing through

(a_{0}, - 2 a_{0}^{2}) : y = - 4 a_{0} x + 2 a_{0}^{2}

y = - 4 a_{0} x + 2 a_{0}^{2}

\int 9 x^{2} - 8 x d x

\int \frac{3}{1 + 9 x ^{2}} d x

\int \frac{y ^{2} - 4}{y} d y

\frac{d}{d x} (\frac{x ^{5} - 8 x ^{3} + x + 6}{x})

x \to 0 lim (2 x^{3} - 4 x + 2)