What is the d/(dt)(t-cos(t)) ?

The d/(dt)(t-cos(t)) is 1+sin(t)

What is the first d/(dt)(t-cos(t)) ?

The first d/(dt)(t-cos(t)) is 1+sin(t)

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\frac{d}{d t} (t - cos (t))

1 + sin (t)

Solution steps

\frac{d}{d t} (t - cos (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d t}{d t} - \frac{d}{d t} (cos (t))

\frac{d t}{d t} = 1

\frac{d}{d t} (cos (t)) = - sin (t)

= 1 - (- sin (t))

Simplify

= 1 + sin (t)

x \to + 2 lim (x 13 - x^{2})

\int 1 + \frac{2}{x} d x

\frac{d}{d x} (cos (sin (5 x^{2})))

\frac{d}{d x} (\frac{x ^{3} - 1}{x ^{3} + 1})

y^{^{''}} + y = cos (t)