What is the derivative of (-16x^2+1)^2 ?

The derivative of (-16x^2+1)^2 is -64x(-16x^2+1)

What is the first derivative of (-16x^2+1)^2 ?

The first derivative of (-16x^2+1)^2 is -64x(-16x^2+1)

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derivative of

(- 16 x^{2} + 1)^{2}

- 64 x (- 16 x^{2} + 1)

Solution steps

\frac{d}{d x} ((- 16 x^{2} + 1)^{2})

Apply the chain rule:

2 (- 16 x^{2} + 1) \frac{d}{d x} (- 16 x^{2} + 1)

= 2 (- 16 x^{2} + 1) \frac{d}{d x} (- 16 x^{2} + 1)

\frac{d}{d x} (- 16 x^{2} + 1) = - 32 x

= 2 (- 16 x^{2} + 1) (- 32 x)

Simplify

= - 64 x (- 16 x^{2} + 1)

y^{^{''}} = sin (x)

x (\frac{d y}{d x}) - y = (\frac{x ^{3}}{y}) e^{\frac{y}{x}}

x \to 0 lim (\frac{e ^{∣ x ∣} - 1}{x})

\frac{d y}{d t} = \frac{4 t}{k} - 0.1 y t

\int_{0}^{π} 8 sin^{4} (x) d x

What is the derivative of (-16x^2+1)^2 ?
The derivative of (-16x^2+1)^2 is -64x(-16x^2+1)
What is the first derivative of (-16x^2+1)^2 ?
The first derivative of (-16x^2+1)^2 is -64x(-16x^2+1)