What is (\partial)/(\partial x)(4xy-3x^2) ?

The answer to (\partial)/(\partial x)(4xy-3x^2) is 4y-6x

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(\partial)/(\partial x)(4xy-3x^2)

\frac{\partial}{\partial x} (4 x y - 3 x^{2})

4 y - 6 x

Solution steps

\frac{\partial}{\partial x} (4 x y - 3 x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x y) - \frac{\partial}{\partial x} (3 x^{2})

\frac{\partial}{\partial x} (4 x y) = 4 y

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

= 4 y - 6 x

y^{^{'}} = 2 x, y (1) = 7

x y^{^{'}} = x^{2} sin (x) + y

f (x) = \frac{36 x}{x ^{2} + 36}

\int \frac{( 4 x ^{2} )}{( x - 2 ) ( x ^{2} + 4 )} d x

\int \frac{x ^{n}}{n} d x

What is (\partial)/(\partial x)(4xy-3x^2) ?
The answer to (\partial)/(\partial x)(4xy-3x^2) is 4y-6x