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Popular Calculus >

(xe^x)^'

Solution

(x e^{x})^{^{'}}

Solution

e^{x} + e^{x} x

Solution steps

(x e^{x})^{'}

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= x^{^{'}} e^{x} + (e^{x})^{^{'}} x

x^{'} = 1

(e^{x})^{'} = e^{x}

= 1 \cdot e^{x} + e^{x} x

Simplify

= e^{x} + e^{x} x

Graph

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integral of 1/(z^2+6z+10)

derivative of 3x^2+7x-2

Frequently Asked Questions (FAQ)

What is the (xe^x)^' ?
The (xe^x)^' is e^x+e^xx
What is the first (xe^x)^' ?
The first (xe^x)^' is e^x+e^xx