What is factor cos^2(ln(e^{2x+1}(-2x))) ?

The solution to factor cos^2(ln(e^{2x+1}(-2x))) is cos^2(ln(-2e^{2x+1}x))

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factor cos^2(ln(e^{2x+1}(-2x)))

factor

cos^{2} (ln (e^{2 x + 1} (- 2 x)))

cos^{2} (ln (- 2 e^{2 x + 1} x))

Solution steps

cos^{2} (ln (e^{2 x + 1} (- 2 x)))

Remove parentheses:

(- a) = - a

= cos^{2} (ln (- e^{2 x + 1} \cdot 2 x))

\frac{3 e ^{- π s}}{s ^{2} + 9}

f (x) = 4 x^{2} - 1, (- 6, 3)

y^{^{'}} = (x + y - 2)^{2}, y (0) = 0

2 cos (π t)

\frac{\partial}{\partial y} ((x - 5)^{\frac{1}{4}} y^{\frac{1}{4}})

What is factor cos^2(ln(e^{2x+1}(-2x))) ?
The solution to factor cos^2(ln(e^{2x+1}(-2x))) is cos^2(ln(-2e^{2x+1}x))