What is the integral from 1 to infinity of (e^{-x}) ?

The integral from 1 to infinity of (e^{-x}) is 1/e

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integral from 1 to infinity of (e^{-x})

\int_{1}^{\infty} (e^{- x}) d x

\frac{1}{e}

Decimal Notation

0.36787 \dots

Solution steps

\int_{1}^{\infty} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{1}^{\infty} (e^{- x}) d x = 0 - (- \frac{1}{e})

= 0 - (- \frac{1}{e})

Simplify

= \frac{1}{e}

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4 ln (x)

What is the integral from 1 to infinity of (e^{-x}) ?
The integral from 1 to infinity of (e^{-x}) is 1/e