What is the tangent of 2x^2+3x,\at x=1 ?

The tangent of 2x^2+3x,\at x=1 is y=7x-2

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tangent of 2x^2+3x,\at x=1

tangent of

2 x^{2} + 3 x, at x = 1

y = 7 x - 2

Solution steps

Find the tangent point:

(1, 5)

Find the slope of

y = 2 x^{2} + 3 x : \frac{d y}{d x} = 4 x + 3

Compute the slope of

y = 2 x^{2} + 3 x

x = 1 : m = 7

Find the line with slope m=

7

and passing through

(1, 5) : y = 7 x - 2

y = 7 x - 2

f (x) = 5 x - 3

n = 1 \sum \infty n^{(- \frac{1}{2})}

2 x + \frac{3}{x}

\frac{\partial}{\partial x} (2 x + 5 y + 3)

(y + 1) \frac{d y}{d x} = 2 x

What is the tangent of 2x^2+3x,\at x=1 ?
The tangent of 2x^2+3x,\at x=1 is y=7x-2