What is the limit as x approaches-1 of arccos(x) ?

The limit as x approaches-1 of arccos(x) is pi

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limit as x approaches-1 of arccos(x)

x \to - 1 lim (arccos (x))

π

Solution steps

x \to - 1 lim (arccos (x))

Plug in the value

x = - 1

= arccos (- 1)

Use the following trivial identity:

arccos (- 1) = π

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π

\int_{0}^{π} 3 sin^{2} (x co) s^{4} x d x

x \to 7 lim (\frac{( \frac{1}{x} - \frac{1}{7} )}{x - 7})

\int \frac{x ^{3}}{x ^{8} + 16} d x

\frac{d}{d x} (x^{2} (1 - x)^{2})

4 sin (θ) - θ

What is the limit as x approaches-1 of arccos(x) ?
The limit as x approaches-1 of arccos(x) is pi