What is the tangent of f(x)=4tan(x),\at x= pi/3 ?

The tangent of f(x)=4tan(x),\at x= pi/3 is y=16x+4sqrt(3)-(16pi)/3

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tangent of f(x)=4tan(x),\at x= pi/3

tangent of

f (x) = 4 tan (x), at x = \frac{π}{3}

y = 16 x + 43 - \frac{16 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 43)

Find the slope of

f (x) = 4 tan (x) : \frac{df ( x )}{d x} = 4 sec^{2} (x)

Compute the slope of

f (x) = 4 tan (x)

x = \frac{π}{3} : m = 16

Find the line with slope m=

16

and passing through

(\frac{π}{3}, 43) : y = 16 x + 43 - \frac{16 π}{3}

y = 16 x + 43 - \frac{16 π}{3}

\int_{0}^{3} π (9 - x^{2})^{2} d x

x \to 0 + lim (\frac{x ^{3} + 3}{x})

x \to 4 lim (6 - x)

\frac{d}{d x} (e^{3 x} x)

\frac{d}{d x} (csc (x) \cdot cot (x))

What is the tangent of f(x)=4tan(x),\at x= pi/3 ?
The tangent of f(x)=4tan(x),\at x= pi/3 is y=16x+4sqrt(3)-(16pi)/3