What is the derivative of A*sin(kx-ωt) ?

The derivative of A*sin(kx-ωt) is Acos(kx-ωt)k

What is the first derivative of A*sin(kx-ωt) ?

The first derivative of A*sin(kx-ωt) is Acos(kx-ωt)k

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (A \cdot sin (k x - ω t))

A cos (k x - ω t) k

Solution steps

\frac{d}{d x} (A sin (k x - ω t))

Treat

A, k, ω, t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= A \frac{d}{d x} (sin (k x - ω t))

Apply the chain rule:

cos (k x - ω t) \frac{d}{d x} (k x - ω t)

= cos (k x - ω t) \frac{d}{d x} (k x - ω t)

\frac{d}{d x} (k x - ω t) = k

= A cos (k x - ω t) k

\int_{2}^{3} \frac{21}{3 - x} d x

\int cos (π t) d t

y = x (27 x^{- 2} + 4)

x \to + 2 + lim (\frac{x}{x - 2})

\int x \cdot e^{- s x} d x

What is the derivative of A*sin(kx-ωt) ?
The derivative of A*sin(kx-ωt) is Acos(kx-ωt)k
What is the first derivative of A*sin(kx-ωt) ?
The first derivative of A*sin(kx-ωt) is Acos(kx-ωt)k