What is the (1/((4-x)^2))^' ?

The (1/((4-x)^2))^' is 2/((4-x)^3)

What is the first (1/((4-x)^2))^' ?

The first (1/((4-x)^2))^' is 2/((4-x)^3)

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(\frac{1}{( 4 - x ) ^{2}})^{^{'}}

\frac{2}{( 4 - x ) ^{3}}

Solution steps

(\frac{1}{( 4 - x ) ^{2}})^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= ((4 - x)^{- 2})^{^{'}}

Apply the chain rule:

- \frac{2}{( 4 - x ) ^{3}} (4 - x)^{'}

= - \frac{2}{( 4 - x ) ^{3}} (4 - x)^{'}

(4 - x)^{'} = - 1

= - \frac{2}{( 4 - x ) ^{3}} (- 1)

Simplify

= \frac{2}{( 4 - x ) ^{3}}

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