What is (\partial)/(\partial x)(cos(kx)) ?

The answer to (\partial)/(\partial x)(cos(kx)) is -sin(kx)k

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(\partial)/(\partial x)(cos(kx))

\frac{\partial}{\partial x} (cos (k x))

- sin (k x) k

Solution steps

\frac{\partial}{\partial x} (cos (k x))

Apply the chain rule:

- sin (k x) \frac{\partial}{\partial x} (k x)

= - sin (k x) \frac{\partial}{\partial x} (k x)

\frac{\partial}{\partial x} (k x) = k

= - sin (k x) k

(- 4, 3), (- 1, - 6)

\int x^{2} 4 - x^{2} d x

\int (z + 1) e^{3 z} d z

y^{3} + 3 y^{2} = x^{4} - 3 x^{2}, (- 2, 1)

\int 3 x (x - 2) d x

What is (\partial)/(\partial x)(cos(kx)) ?
The answer to (\partial)/(\partial x)(cos(kx)) is -sin(kx)k