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Popular >

area 4x^2+y=4,x^8-y=1

Solution

area

4 x^{2} + y = 4, x^{8} - y = 1

Solution

\frac{64}{9}

+1

Decimal Notation

7.11111 \dots

Solution steps

Isolate

y

for

4 x^{2} + y = 4 : y = 4 - 4 x^{2}

Isolate

y

for

x^{8} - y = 1 : y = - 1 + x^{8}

Apply the area formula:

\int_{- 1}^{1} 4 - 4 x^{2} - (- 1 + x^{8}) d x

Solve

\int_{- 1}^{1} 4 - 4 x^{2} - (- 1 + x^{8}) d x : \frac{64}{9}

The area is:

= \frac{64}{9}

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Frequently Asked Questions (FAQ)

What is area 4x^2+y=4,x^8-y=1 ?
The answer to area 4x^2+y=4,x^8-y=1 is 64/9