What is (\partial)/(\partial x)(8x^2y-3) ?

The answer to (\partial)/(\partial x)(8x^2y-3) is 16xy

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(\partial)/(\partial x)(8x^2y-3)

\frac{\partial}{\partial x} (8 x^{2} y - 3)

16 x y

Solution steps

\frac{\partial}{\partial x} (8 x^{2} y - 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{2} y) - \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (8 x^{2} y) = 16 y x

\frac{\partial}{\partial x} (3) = 0

= 16 y x - 0

Simplify

= 16 x y

x \to - 2 lim (- x^{2} - 4 x)

\int_{0}^{1} (2 x) d x

\frac{4 x - 9}{x - 9}

x \to 0 - lim (x^{2} + \frac{1}{x})

\frac{2}{1 - x ^{2}}

What is (\partial)/(\partial x)(8x^2y-3) ?
The answer to (\partial)/(\partial x)(8x^2y-3) is 16xy